Integrand size = 11, antiderivative size = 50 \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=\frac {x}{b}-\frac {2 a \arctan \left (\frac {b+a \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{b \sqrt {a^2-b^2}} \]
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Time = 0.05 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.364, Rules used = {2814, 2739, 632, 210} \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=\frac {x}{b}-\frac {2 a \arctan \left (\frac {a \tan \left (\frac {x}{2}\right )+b}{\sqrt {a^2-b^2}}\right )}{b \sqrt {a^2-b^2}} \]
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Rule 210
Rule 632
Rule 2739
Rule 2814
Rubi steps \begin{align*} \text {integral}& = \frac {x}{b}-\frac {a \int \frac {1}{a+b \sin (x)} \, dx}{b} \\ & = \frac {x}{b}-\frac {(2 a) \text {Subst}\left (\int \frac {1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac {x}{2}\right )\right )}{b} \\ & = \frac {x}{b}+\frac {(4 a) \text {Subst}\left (\int \frac {1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac {x}{2}\right )\right )}{b} \\ & = \frac {x}{b}-\frac {2 a \arctan \left (\frac {b+a \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{b \sqrt {a^2-b^2}} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.94 \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=\frac {x-\frac {2 a \arctan \left (\frac {b+a \tan \left (\frac {x}{2}\right )}{\sqrt {a^2-b^2}}\right )}{\sqrt {a^2-b^2}}}{b} \]
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Time = 0.32 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.08
method | result | size |
default | \(-\frac {2 a \arctan \left (\frac {2 a \tan \left (\frac {x}{2}\right )+2 b}{2 \sqrt {a^{2}-b^{2}}}\right )}{b \sqrt {a^{2}-b^{2}}}+\frac {2 \arctan \left (\tan \left (\frac {x}{2}\right )\right )}{b}\) | \(54\) |
risch | \(\frac {x}{b}-\frac {i a \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a +a^{2}-b^{2}\right )}{\sqrt {a^{2}-b^{2}}\, b}\right )}{\sqrt {a^{2}-b^{2}}\, b}+\frac {i a \ln \left ({\mathrm e}^{i x}+\frac {i \left (\sqrt {a^{2}-b^{2}}\, a -a^{2}+b^{2}\right )}{\sqrt {a^{2}-b^{2}}\, b}\right )}{\sqrt {a^{2}-b^{2}}\, b}\) | \(135\) |
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Time = 0.32 (sec) , antiderivative size = 192, normalized size of antiderivative = 3.84 \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=\left [-\frac {\sqrt {-a^{2} + b^{2}} a \log \left (-\frac {{\left (2 \, a^{2} - b^{2}\right )} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2} - 2 \, {\left (a \cos \left (x\right ) \sin \left (x\right ) + b \cos \left (x\right )\right )} \sqrt {-a^{2} + b^{2}}}{b^{2} \cos \left (x\right )^{2} - 2 \, a b \sin \left (x\right ) - a^{2} - b^{2}}\right ) - 2 \, {\left (a^{2} - b^{2}\right )} x}{2 \, {\left (a^{2} b - b^{3}\right )}}, \frac {\sqrt {a^{2} - b^{2}} a \arctan \left (-\frac {a \sin \left (x\right ) + b}{\sqrt {a^{2} - b^{2}} \cos \left (x\right )}\right ) + {\left (a^{2} - b^{2}\right )} x}{a^{2} b - b^{3}}\right ] \]
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Leaf count of result is larger than twice the leaf count of optimal. 155 vs. \(2 (37) = 74\).
Time = 10.83 (sec) , antiderivative size = 155, normalized size of antiderivative = 3.10 \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=\begin {cases} \tilde {\infty } x & \text {for}\: a = 0 \wedge b = 0 \\\frac {x}{b} & \text {for}\: a = 0 \\- \frac {\cos {\left (x \right )}}{a} & \text {for}\: b = 0 \\\frac {x \tan {\left (\frac {x}{2} \right )}}{b \tan {\left (\frac {x}{2} \right )} - b} - \frac {x}{b \tan {\left (\frac {x}{2} \right )} - b} + \frac {2}{b \tan {\left (\frac {x}{2} \right )} - b} & \text {for}\: a = - b \\\frac {x \tan {\left (\frac {x}{2} \right )}}{b \tan {\left (\frac {x}{2} \right )} + b} + \frac {x}{b \tan {\left (\frac {x}{2} \right )} + b} + \frac {2}{b \tan {\left (\frac {x}{2} \right )} + b} & \text {for}\: a = b \\- \frac {a \log {\left (\tan {\left (\frac {x}{2} \right )} + \frac {b}{a} - \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{b \sqrt {- a^{2} + b^{2}}} + \frac {a \log {\left (\tan {\left (\frac {x}{2} \right )} + \frac {b}{a} + \frac {\sqrt {- a^{2} + b^{2}}}{a} \right )}}{b \sqrt {- a^{2} + b^{2}}} + \frac {x}{b} & \text {otherwise} \end {cases} \]
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Exception generated. \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=\text {Exception raised: ValueError} \]
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Time = 0.32 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.16 \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=-\frac {2 \, {\left (\pi \left \lfloor \frac {x}{2 \, \pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (a\right ) + \arctan \left (\frac {a \tan \left (\frac {1}{2} \, x\right ) + b}{\sqrt {a^{2} - b^{2}}}\right )\right )} a}{\sqrt {a^{2} - b^{2}} b} + \frac {x}{b} \]
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Time = 6.63 (sec) , antiderivative size = 101, normalized size of antiderivative = 2.02 \[ \int \frac {\sin (x)}{a+b \sin (x)} \, dx=\frac {x}{b}-\frac {2\,a\,\mathrm {atanh}\left (\frac {\sin \left (\frac {x}{2}\right )\,a^4-\cos \left (\frac {x}{2}\right )\,a^3\,b-3\,\sin \left (\frac {x}{2}\right )\,a^2\,b^2+\cos \left (\frac {x}{2}\right )\,a\,b^3+2\,\sin \left (\frac {x}{2}\right )\,b^4}{{\left (b^2-a^2\right )}^{3/2}\,\left (2\,b\,\sin \left (\frac {x}{2}\right )+a\,\cos \left (\frac {x}{2}\right )\right )}\right )}{b\,\sqrt {b^2-a^2}} \]
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